BiologyChapter 14: Evolution
Hardy-Weinberg Named — Little Sums
If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers.
Learning objectives
- Define little sums using accurate biology terms.
- Explain why little sums matters within hardy-weinberg named.
- Apply the learning unit to an FBISE-style example, comparison, diagram, or calculation.
Definition
If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. This page separates the idea from the wider topic “HARDY-WEINBERG NAMED” so it can be revised and assessed on its own.
Mathematical form
q = 0.1
p = 0.9
p = 1
q = sqrt(q2)
Important terms
- LITTLE SUMS
- If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers.
- HARDY-WEINBERG NAMED
- A null model: if no selection, no mutation, no migration, no chance wobble, and random mating, allele frequencies stay put.
Overview
Study this learning unit in three steps:
Key Idea
If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working.
Examples q = sqrt(q^2) · p = 1 - q · 2pq carriers
Exam Application
Worked: recessive phenotype 1% (q^2 = 0.01). q = 0.1 p = 0.9 2pq = 2 x 0.9 x 0.1 = 0.18 Carriers about 18%.
Examples q = sqrt(q^2) · p = 1 - q · 2pq carriers
WHAT — HARDY-WEINBERG NAMED — LITTLE SUMS
If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. This page separates the idea from the wider topic “HARDY-WEINBERG NAMED” so it can be revised and assessed on its own.
WHY — Why this topic matters
HARDY-WEINBERG NAMED — LITTLE SUMS is an independent FBISE learning unit because students must connect its structures and processes with their biological functions and examples.
HOW — How it works
If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. Examples: q = sqrt(q^2); p = 1 - q; 2pq carriers. Exam use: Worked: recessive phenotype 1% (q^2 = 0.01). q = 0.1 p = 0.9 2pq = 2 x 0.9 x 0.1 = 0.18 Carriers about 18%.
Worked example
- If q2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. Examples: q = sqrt(q^2); p = 1 - q; 2pq carriers. Exam use: Worked: recessive phenotype 1% (q^2 = 0.01).
- q = 0.1
- p = 0.9
- 2pq = 2 x 0.9 x 0.1 = 0.18
- Carriers about 18%.
In simple words
Federal Board Class 11 Biology learning unit. Easy wording; no provincial-board material added.
Key points
- q from the recessive class
- 2pq = 0.18
Exam preparation
Exam Focus
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Hardy-Weinberg Named — Little Sums
Sticky Notes · Quick Revision
Core idea
- If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. This page separates the idea from the wider topic “HARDY-WEINBERG NAMED” so it can be revised and assessed on its own.
WHAT
- If q2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers.
WHY
- HARDY-WEINBERG NAMED — LITTLE SUMS is an independent FBISE learning unit because students must connect its structures and processes with their biological functions and examples.
HOW
- If q^2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers. Show the square root step. Do not invent data. q² = frequency of aa (recessive homozygotes). q = √q². p = 1 − q. p² = AA frequency. 2pq = Aa carrier frequency. Show all working. Examples: q = sqrt(q^2); p = 1 - q; 2pq carriers. Exam use: Worked: recessive phenotype 1% (q^2 = 0.01). q = 0.1 p = 0.9 2pq = 2 x 0.9 x 0.1 = 0.18 Carriers about 18%.
Common misconception
- Do not treat little sums as the same as every other part of hardy-weinberg named; define this unit and use its own evidence, steps, or conditions.
FBISE exam check
- Define hardy-weinberg named — little sums, explain how it works, and support the answer with one relevant example.
60-second revision
- If q2 = 0.01, q = 0.1, p = 0.9, 2pq = 0.18 carriers.
- q = sqrt(q2)
- Exam link: q from the recessive class.
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