ChemistryChapter 4: Stoichiometry
4.1 Mole
Mole:
Explanation level
This topic explains the mole concept — what it is, how it is used, and its relationship with Avogadro's number, molar mass, and molar volume.
Definition
Mole: The amount of substance that contains 6.023 × 1023 representative particles.
Avogadro's Number: The experimentally determined number 6.023 × 1023, which represents the number of particles in one mole of a substance.
Main Idea
Chemists use the mole as the SI unit to weigh and count atoms, molecules, and ions. Just as a dozen represents 12 identical things, a mole represents 6.023 × 1023 particles of a substance. The atomic mass, formula mass, and molecular weight of a substance in grams are equal to one mole of the substance.
Core Concept
- 1 mole = 6.023 × 1023 representative particles (atoms, molecules, or ions).
- 1 mole of any substance = its atomic mass, formula mass, or molecular mass in grams.
- 1 mole of any gas at STP occupies 22.414 dm³ (molar volume).
Detailed Explanation
What is a Mole?
- A mole is the amount of substance that contains 6.023 × 1023 representative particles.
- This experimentally determined number is called Avogadro's number.
- Just as a dozen represents 12 identical things, a mole represents 6.023 × 1023 particles of a substance.
- A mole of carbon is 6.023 × 1023 carbon atoms.
- A mole of sodium is 6.023 × 1023 Na atoms.
- One mole of water is 6.023 × 1023 H₂O molecules.
Representative Particles
- Atoms
- Molecules
- Ions
This relationship allows us to convert moles into representative particles and vice versa.
Mole and Mass
The atomic mass, formula mass, and molecular weight of a substance in grams are equal to one mole of the substance.
- One mole of O atoms = **16 g**
- One mole of O₂ molecules = **32 g**
- One mole of H₂O molecules = **18 g**
- One mole of Na ions = **23 g**
- One mole of NaCl formula units = 58.5 g
Molar Volume (Vm)
- One mole of any gas at STP (standard temperature and pressure) occupies a volume of 22.414 dm³.
- This volume is called molar volume.
- With the help of this relationship, we can convert the mass of a gas at STP into its volume and vice versa.
- 22.414 dm³ of any gas at STP = 1 mole = 6.02 × 1023 molecules.
- 22.414 dm³ of H₂ gas at STP = 2 g = 6.02 × 1023 molecules.
- 22.414 dm³ of NH₃ gas at STP = 17 g = 6.02 × 1023 molecules.
Example 4.1: Volume of 2.5 Moles of Chlorine at STP
Solution: We know that: 22.414 dm3 of Cl2 at STP = 1 mole
Or 1 mole of Cl₂ occupies a volume of 22.414 dm³ at STP.
2.5 mole of Cl2 occupy a volume of 22.414 dm3 × 2.5 = 56.035 dm3
Molar Mass and Density of Gases
- Density is defined as the mass per unit volume of a substance.
- As the molar mass of all gases occupies the same volume at STP, the density of a gas depends on its molar mass.
- A gas having higher molar mass will have higher density and vice versa.
- Density of a gas can be calculated from its molar mass and molar volume.
- If the density of a gas at STP is determined, its molar mass can be calculated.
Example 4.2: Gram Molecular Mass from Density
Problem: Calculate the gram molecular mass of a gas which has a density of 1.43 g/dm3 at STP.
Solution: 1 dm3 of gas at STP = 1.43 g 22.4 dm3 of gas at STP = 1.43 × 22.4 = 32.032 g
As 22.4 dm3 of a gas at STP = molar mass
Therefore, gram molecular mass of gas is 32.032 amu.
Intermediate Level
Key Relationships
| Quantity | Relationship |
|---|---|
| 1 mole | 6.023 × 1023 particles |
| 1 mole of atoms | Atomic mass in grams |
| 1 mole of molecules | Molecular mass in grams |
| 1 mole of ions | Ionic mass in grams |
| 1 mole of gas at STP | 22.414 dm³ |
Examples
- 1 mole O = 16 g
- 1 mole O₂ = 32 g
- 1 mole H₂O = 18 g
- 1 mole Na⁺ = 23 g
- 1 mole NaCl = 58.5 g
Molar Volume
- 22.414 dm³ of any gas at STP = 1 mole = 6.02 × 1023 molecules.
- This is called molar volume.
Density and Molar Mass
Density = MassVolume
For gases at STP: Molar mass = Density × 22.414
Important Points
- 1. 1 mole = 6.023 × 1023 particles.
- 2. Avogadro's number = 6.023 × 1023.
- 3. 1 mole of atoms = atomic mass in grams.
- 4. 1 mole of molecules = molecular mass in grams.
- 5. 1 mole of any gas at STP = 22.414 dm³.
- 6. Molar volume = 22.414 dm³.
- 7. Density = mass/volume.
- 8. Molar mass = density × 22.414.
Remember
- - 1 mole: 6.023 × 1023 particles
- - 1 mole of atoms: Atomic mass in grams
- - 1 mole of molecules: Molecular mass in grams
- - 1 mole of gas at STP: 22.414 dm³
- - Molar volume: 22.414 dm³
- - Molar mass: Density × 22.414
Common Mistakes
- 1. Confusing mole with mass: 1 mole of different substances has different masses.
- 2. Forgetting Avogadro's number: 6.023 × 1023.
- 3. Thinking molar volume applies to all conditions: It applies at STP only.
- 4. Mixing up atomic mass and molecular mass: Atomic mass = 1 atom; molecular mass = 1 molecule.
Quick Revision
- 1 mole = 6.023 × 1023 particles.
- Avogadro's number = 6.023 × 1023.
- 1 mole of atoms = atomic mass in grams.
- 1 mole of molecules = molecular mass in grams.
- 1 mole of any gas at STP = 22.414 dm³.
- Molar volume = 22.414 dm³.
- Density = mass/volume.
- Molar mass = density × 22.414.
60-Second Revision
- 1 mole: 6.023 × 1023 particles
- 1 mole of atoms: Atomic mass in grams
- 1 mole of molecules: Molecular mass in grams
- 1 mole of gas at STP: 22.414 dm³
- Molar volume: 22.414 dm³
- Molar mass: Density × 22.414
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- Chapter: 4 (Stoichiometry)
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Review the key facts, formulas and checks before you move on.4.1 Mole
Sticky Notes · Quick Revision
Key Point 1
- 1 mole: 6.023 × 1023 particles
Key Point 2
- 1 mole of atoms: Atomic mass in grams
Key Point 3
- 1 mole of molecules: Molecular mass in grams
Key Point 4
- 1 mole of gas at STP: 22.414 dm³
Key Point 5
- Molar volume: 22.414 dm³
Key Point 6
- Molar mass: Density × 22.414
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