MathematicsChapter 2: Quadratic Equations
Completing the Square
For x^2 + px, add (p/2)^2 to make (x + p/2)^2.
Learning objectives
- Explain completing the square using the correct definitions, conditions, and notation.
- Apply add (half of b)^2, then square root correctly in routine and exam-style questions.
- Show each important step, simplify the result, and check that it satisfies the original conditions.
Definition
For x^2 + px, add (p/2)^2 to make (x + p/2)^2. Then move the leftover constant. This solves quadratics that do not factor nicely, and it is how the formula is born.
Mathematical form
x = 2 + sqrt(3) or x = 2 - sqrt(3)
x = 2 + sqrt(3) or x
Where / symbols
- COMPLETING THE SQUARE
- For x^2 + px, add (p/2)^2 to make (x + p/2)^2. Then move the leftover constant. This solves quadratics that do not factor nicely, and it is how the formula is born.
- THE NUMBER TO ADD
- x^2 + 6x needs 3^2 = 9. x^2 - 4x needs (-2)^2 = 4. Always square half of the x-coefficient (when a=1).
- SOLVE
- x^2 - 4x + 1 = 0 -> (x-2)^2 - 4 + 1 = 0 -> (x-2)^2 = 3 -> x-2 = +/- sqrt(3) -> x = 2 +/- sqrt(3).
Overview
Half, square, move:
The Number To Add
x^2 + 6x needs 3^2 = 9. x^2 - 4x needs (-2)^2 = 4. Always square half of the x-coefficient (when a=1).
Examples x^2+6x -> +9 · x^2-4x -> +4 · Not +6 or +16
Solve
x2 - 4x + 1 = 0 -> (x-2)2 - 4 + 1 = 0 -> (x-2)2 = 3 -> x-2 = +/- sqrt(3) -> x = 2 +/- sqrt(3).
Examples (x-2)^2 = 3 · x = 2 +/- sqrt(3) · Two real roots
WHAT — COMPLETING THE SQUARE
For x^2 + px, add (p/2)^2 to make (x + p/2)^2. Then move the leftover constant. This solves quadratics that do not factor nicely, and it is how the formula is born. The symbols and conditions are part of the mathematics, so include them when stating the rule.
WHY — Why this topic matters
Completing The Square matters because quadratic equations model areas, motion, and many algebraic relationships. Knowing more than one solution method lets you choose the quickest reliable method and check the nature of the roots.
HOW — How to solve and explain it
Start by identifying what is given and what must be found. Work through THE NUMBER TO ADD, then SOLVE. Worked: solve x^2 - 4x + 1 = 0 by completing the square. x^2 - 4x + 1 = 0 x^2 - 4x = -1 half of -4 is -2, and (-2)^2 = 4 x^2 - 4x + 4 = -1 + 4 (x - 2)^2 = 3 x - 2 = +/- sqrt(3) x = 2 + sqrt(3) or x = 2 - sqrt(3) Finish by checking signs, restrictions, units, and whether the answer matches the question.
Worked example
- solve x^2 - 4x + 1 = 0 by completing the square.
- x2 - 4x + 1 = 0
- x2 - 4x = -1
- half of -4 is -2, and (-2)2 = 4
- x2 - 4x + 4 = -1 + 4
- (x - 2)2 = 3
- x - 2 = +/- sqrt(3)
- x = 2 + sqrt(3) or x = 2 - sqrt(3)
In simple words
If a is not 1, divide the whole equation by a first, then complete the square.
Key points
- add (half of b)^2
- then square root
- (b/2)2 if a=1
- isolate the square
Exam preparation
Exam Focus
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Completing the Square
Sticky Notes · Quick Revision
Core Idea
- For x^2 + px, add (p/2)^2 to make (x + p/2)^2. Then move the leftover constant. This solves quadratics that do not factor nicely, and it is how the formula is born.
THE NUMBER TO ADD
- x^2 + 6x needs 3^2 = 9. x^2 - 4x needs (-2)^2 = 4. Always square half of the x-coefficient (when a=1).
SOLVE
- x2 - 4x + 1 = 0 -> (x-2)2 - 4 + 1 = 0 -> (x-2)2 = 3 -> x-2 = +/- sqrt(3) -> x = 2 +/- sqrt(3).
Worked Method
- Worked: solve x^2 - 4x + 1 = 0 by completing the square.
- x2 - 4x + 1 = 0
- x2 - 4x = -1
- half of -4 is -2, and (-2)2 = 4
- x2 - 4x + 4 = -1 + 4
- (x - 2)2 = 3
- x - 2 = +/- sqrt(3)
- x = 2 + sqrt(3) or x = 2 - sqrt(3)
Common Misconception
- If a is not 1, divide the whole equation by a first, then complete the square.
FBISE Exam Check
- If a is not 1, divide the whole equation by a first, then complete the square.
60-second revision
- For x^2 + px, add (p/2)^2 to make (x + p/2)^2.
- THE NUMBER TO ADD: x2 + 6x needs 32 = 9.
- SOLVE: x^2 - 4x + 1 = 0 -> (x-2)^2 - 4 + 1 = 0 -> (x-2)^2 = 3 -> x-2 = +/- sqrt(3) -> x = 2 +/- sqrt(3).
- Worked-method reminder: x = 2 + sqrt(3) or x = 2 - sqrt(3)
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