PhysicsChapter 8: Heat and Thermodynamics
Entropy and Its Sign Convention
Explanation level
Overview
Entropy is a thermodynamic state variable that measures energy dispersal and the part of thermal energy unavailable for useful work; for reversible heat transfer, ΔS = Qrev/T.
Learning Outcomes
- Entropy S is a thermodynamic state variable.
- For reversible heat transfer at temperature T, ΔS = Qrev/T.
- The SI unit of entropy is joule per kelvin, J K⁻¹.
- Heat absorbed by a system gives positive ΔS; heat removed gives negative ΔS.
- Entropy change depends only on initial and final states, although the calculation uses a reversible path.
- Heat flowing spontaneously from hot to cold produces a positive total entropy change.
Intermediate Level
Meaning of Entropy
Rudolf Clausius introduced entropy to express the second law quantitatively. Entropy is often linked with molecular disorder, but a more precise idea is energy dispersal and reduced availability of thermal energy for conversion into mechanical work.
Entropy-Change Equation
When a system absorbs reversible heat Qrev at constant absolute temperature T, its entropy change is:
For a process with changing temperature, entropy change is found by adding the small reversible transfers, written generally as ΔS = ∫δQrev/T. At this level, constant-temperature examples use Qrev/T directly.
Sign Convention
| Heat direction | Q for system | ΔS of system |
|---|---|---|
| absorbed by system | positive | positive at fixed T |
| removed from system | negative | negative at fixed T |
Heat Flow from Hot to Cold
Suppose heat Q leaves a hot body at T₁ and enters a colder body at T₂, where T₁ > T₂. The hot body loses entropy, while the cold body gains a larger amount.
Entropy from Reversible Heat Absorption
A system reversibly absorbs 600 J at a constant temperature of 300 K. Find its entropy change.
ΔS = Qrev/T
ΔS = 600 J / 300 K
Final answer: ΔS = +2.0 J K⁻¹
Entropy during Heat Removal
A body reversibly loses 840 J at 420 K. Find ΔS.
Heat removed means Qrev = −840 J
ΔS = −840420
Final answer: ΔS = −2.0 J K⁻¹
Common Mistakes
- Use kelvin, not Celsius, in QT.
- Include the sign of heat transfer.
- The equation uses reversible heat transfer for calculating a state-function change.
- Entropy is not simply energy; its unit is J K⁻¹.
Short-Question Preparation
Q. Define entropy.
A. A thermodynamic state variable measuring energy dispersal and the thermal energy unavailable for useful work.
Q. Write the entropy-change formula.
A. For reversible transfer at constant T, ΔS = Qrev/T.
Q. State the SI unit.
A. J K⁻¹.
Q. Why is total entropy positive for spontaneous hot-to-cold heat flow?
A. The cold body gains QT₂ while the hot body loses QT₁; since T₂ < T₁, QT₂ is larger.
Sticky Notes
- Entropy S is a thermodynamic state variable.
- For reversible heat transfer at temperature T, ΔS = Qrev/T.
- The SI unit of entropy is joule per kelvin, J K⁻¹.
- Heat absorbed by a system gives positive ΔS; heat removed gives negative ΔS.
- Entropy change depends only on initial and final states, although the calculation uses a reversible path.
- Heat flowing spontaneously from hot to cold produces a positive total entropy change.
60-Second Revision
Entropy is a state variable. For reversible heat transfer at constant T, ΔS = Qrev/T in J K⁻¹. Heat in gives positive ΔS, heat out negative. Hot-to-cold heat flow gives ΔStotal = QT₂ − QT₁ > 0.
Summary
Entropy is a thermodynamic state variable that measures energy dispersal and the part of thermal energy unavailable for useful work; for reversible heat transfer, ΔS = Qrev/T.
Ask-the-Tutor Modes
- Explain entropy simply.
- Apply the sign convention.
- Calculate entropy change.
- Explain the arrow of time.
- Test me with an MCQ.
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Exam preparation
Exam Focus
Important points
- Entropy S is a thermodynamic state variable.
- For reversible heat transfer at temperature T, ΔS = Qrev/T.
- The SI unit of entropy is joule per kelvin, J K⁻¹.
- Heat absorbed by a system gives positive ΔS; heat removed gives negative ΔS.
- Entropy change depends only on initial and final states, although the calculation uses a reversible path.
- Heat flowing spontaneously from hot to cold produces a positive total entropy change.
Common mistakes
- Use kelvin, not Celsius, in QT.
- Include the sign of heat transfer.
- The equation uses reversible heat transfer for calculating a state-function change.
- Entropy is not simply energy; its unit is J K⁻¹.
Quick revision
Revision Zone
Review the key facts, formulas and checks before you move on.Entropy and Its Sign Convention
Sticky Notes · Quick Revision
Key Point 1
- Entropy S is a thermodynamic state variable.
Key Point 2
- For reversible heat transfer at temperature T, ΔS = Qrev/T.
Key Point 3
- The SI unit of entropy is joule per kelvin, J K⁻¹.
Key Point 4
- Heat absorbed by a system gives positive ΔS; heat removed gives negative ΔS.
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- 8 concept questions
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Exam Practice
Important Question
Q1. Define entropy.
Important Question
Q2. Write the entropy-change formula.
Important Question
Q3. State the SI unit.
Important Question
Q4. Why is total entropy positive for spontaneous hot-to-cold heat flow?
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