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Dihybrid Cross
Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both show complete dominance and assort independently. 16 Punnett boxes. Parental types more common; recombinants from assortment. Dihybrid crosses test independent assortment: two genes on different chromosomes assort independently, giving the 9:3
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Dihybrid Cross
What is it?
Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both show complete dominance and assort independently. 16 Punnett boxes. Parental types more common; recombinants from assortment. Dihybrid crosses test independent assortment: two genes on different chromosomes assort independently, giving the 9:3:3:1 ratio when both parents are doubly heterozygous.
In simple words
- Two genes, independent assortment (different chromosomes in the school model).
- 1. GAMETES: A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent).
- 2. WHY 9-3-3-1: 9: both dominant phenotypes.
- Exam reminder: Worked phenotype fractions (R round, Y yellow).
Important terms
DIHYBRID CROSS: Two genes, independent assortment (different chromosomes in the school model).
1. GAMETES: A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent).
2. WHY 9-3-3-1: 9: both dominant phenotypes.
What you should learn
- Explain dihybrid cross in clear biological language.
- Distinguish 1. gametes from 2. why 9-3-3-1.
- Use the key terms to answer a short Federal Board exam question.
Examples
- 16 boxes
- 9 both dominant
- 1 double recessive
GAMETES
A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent). FOIL-like list. If genes are linked, the ratio breaks (next chapter hint). RrYy heterozygote produces four gamete types: RY, Ry, rY, ry (equal proportions if genes on different chromosomes). 4 × 4 = 16-box Punnett for dihybrid.
WHY 9-3-3-1
9: both dominant phenotypes. 3: first dominant second recessive. 3: the other way. 1: both recessive. Each 3 is a recombinant look. 916: both dominant traits. 316: first dominant, second recessive. 316: reversed. 116: both recessive. Each 3 category is a recombinant combination.
Recommended for Class 11
Full school-level explanation
Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both show complete dominance and assort independently. 16 Punnett boxes. Parental types more common; recombinants from assortment. Dihybrid crosses test independent assortment: two genes on different chromosomes assort independently, giving the 9:3:3:1 ratio when both parents are doubly heterozygous.
Two letters, sixteen boxes:
WHAT — DIHYBRID CROSS
Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both show complete dominance and assort independently. 16 Punnett boxes. Parental types more common; recombinants from assortment. Dihybrid crosses test independent assortment: two genes on different chromosomes assort independently, giving the 9:3:3:1 ratio when both parents are doubly heterozygous.
WHY — Why this topic matters
DIHYBRID CROSS is an independent FBISE learning unit because students must connect its structures and processes with their biological functions and examples.
HOW — How it works
GAMETES: A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent). FOIL-like list. If genes are linked, the ratio breaks (next chapter hint). RrYy heterozygote produces four gamete types: RY, Ry, rY, ry (equal proportions if genes on different chromosomes). 4 × 4 = 16-box Punnett for dihybrid. Examples: 16 boxes; 9 both dominant; 1 double recessive. WHY 9-3-3-1: 9: both dominant phenotypes. 3: first dominant second recessive. 3: the other way. 1: both recessive. Each 3 is a recombinant look. 916: both dominant traits. 316: first dominant, second recessive. 316: reversed. 116: both recessive. Each 3 category is a recombinant combination. Examples: RY is 916; rryy is 116; Not 3:1 of a monohybrid. Worked phenotype fractions (R round, Y yellow). Round yellow: 916 Round green: 316 Wrinkled yellow: 316 Wrinkled green: 116
GAMETES
A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent). FOIL-like list. If genes are linked, the ratio breaks (next chapter hint). RrYy heterozygote produces four gamete types: RY, Ry, rY, ry (equal proportions if genes on different chromosomes). 4 × 4 = 16-box Punnett for dihybrid.
Remember
- four gamete types
Examples
- 16 boxes
- 9 both dominant
- 1 double recessive
WHY 9-3-3-1
9: both dominant phenotypes. 3: first dominant second recessive. 3: the other way. 1: both recessive. Each 3 is a recombinant look. 916: both dominant traits. 316: first dominant, second recessive. 316: reversed. 116: both recessive. Each 3 category is a recombinant combination.
Remember
- count boxes
Examples
- RY is 916
- rryy is 116
- Not 3:1 of a monohybrid
Remember
- 9 : 3 : 3 : 1
- independent assortment
- 916, 316, 316, 116
- independent only
- four gamete types
- count boxes
- 9 : 3 : 3 : 1
- independent assortment
How the ideas connect
Worked phenotype fractions (R round, Y yellow). Round yellow: 916 Round green: 316 Wrinkled yellow: 316 Wrinkled green: 116
Deeper understanding
Go beyond memorising Dihybrid Cross. Connect the definition to reasons, relationships, exceptions, and exam wording.
How the ideas connect
Worked phenotype fractions (R round, Y yellow). Round yellow: 916 Round green: 316 Wrinkled yellow: 316 Wrinkled green: 116
Common mistakes
Exam focus
Core Idea
1. GAMETES
2. WHY 9-3-3-1
Exam Example
Exam focus
Quick revision
- 9 : 3 : 3 : 1
- independent assortment
- 916, 316, 316, 116
- independent only
- DIHYBRID CROSS: Two genes, independent assortment (different chromosomes in the school model).
- 1. GAMETES: A heterozygote RrYy makes RY, Ry, rY, ry (equal if independent).
Independent assortment assumed. Linked genes wait for Ch 13.
For long answers on Dihybrid Cross: define clearly → explain the main parts → give one example → state one exam caution.
Exam Focus
Exam Focus
Important points
- 9 : 3 : 3 : 1
- independent assortment
- 916, 316, 316, 116
- independent only
Important formulas
- 9 : 3 : 3 : 1
- independent assortment
- 916, 316, 316, 116
Common exam traps
- Independent assortment assumed. Linked genes wait for Ch 13.
- Do not treat 1. GAMETES and 2. WHY 9-3-3-1 as the same idea; each explains a different part of the topic.
Long question structure
Definition → key parts → example → exam caution
Common Mistakes
Common Mistakes
- Mistake
Independent assortment assumed. Linked genes wait for Ch 13.
- Mistake
Do not treat 1. GAMETES and 2. WHY 9-3-3-1 as the same idea; each explains a different part of the topic.
- Mistake
Writing only “9 : 3 : 3 : 1” is incomplete. Link it with “independent assortment” and explain the biological reason or sequence.
- Mistake
Independent assortment assumed. Linked genes wait for Ch 13.
Revision Zone
60-Second Revision
Quick cues from this topic — use them for last-minute revision.
9 : 3 : 3 : 1
independent assortment
916, 316, 316, 116
independent only
Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both sho
- Definition
- Two genes, independent assortment (different chromosomes in the school model). RrYy x RrYy (round yellow peas school) gives 9 : 3 : 3 : 1 phenotypes if both sho
- Example
- 16 boxes
- Critical warning
- Independent assortment assumed. Linked genes wait for Ch 13.
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Exam Practice
Define
Q1. Define Dihybrid Cross.
Explain
Q2. Explain: GAMETES.
Example
Q3. Give one clear example of Dihybrid Cross and say why it fits.
Mistake
Q4. State one common mistake students make about Dihybrid Cross.
Exam note
Q5. Write a short exam note on Dihybrid Cross: definition, two points, one example.
Sources & References
School-standard facts for Matric and Intermediate. Original explanations — not copied from textbooks.