Topic 6.415 min read
Equation of Continuity
The equation of continuity applies conservation of mass to steady fluid flow. Its general form is ρ₁A₁v₁ = ρ₂A₂v₂; for an incompressible fluid it becomes A₁v₁ = A₂v₂.
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Beginner Level
During steady flow, fluid cannot disappear or collect inside a pipe. The mass entering each second must equal the mass leaving each second. This is the idea behind the equation of continuity.
- A
- cross-sectional area (m²)
- v
- fluid speed (m s⁻¹)
This explains why water speeds up when a hose end is squeezed and why a freely falling stream becomes thinner as it accelerates.
Recommended for Class 11
Equation of Continuity
Overview
The continuity equation is a mathematical statement of conservation of mass in fluid dynamics. It is used for pipes, tubes, ducts, rivers, blood vessels and power-plant systems.
Learning Outcomes
- Derive continuity from conservation of mass.
- Distinguish mass flow rate from volume flow rate.
- Use the general and incompressible forms.
- Explain the inverse area-speed relation.
- Solve single-pipe and branched-flow problems.
- Apply continuity to water jets, hoses, rivers and blood vessels.
Intermediate Level
Derivation from Conservation of Mass
Consider steady flow through a tube whose cross-sectional area changes. During the same short time Δt, fluid at sections 1 and 2 moves distances Δx₁ and Δx₂.
- Δx
- distance moved in time Δt (m)
Each moving portion is a short cylinder. Since volume equals cross-sectional area multiplied by length:
- ΔV
- volume crossing a section (m³)
Using mass = density × volume, the masses crossing the sections are:
- ρ
- fluid density (kg m⁻³)
For steady flow with one entrance, one exit and no source or sink, mass cannot accumulate. Therefore Δm₁ = Δm₂. Cancelling the common time interval gives:
Incompressible Form
For an incompressible fluid, density remains constant, so ρ₁ = ρ₂. The densities cancel from the general equation.
Volume Flow Rate
Volume flow rate Q is the volume passing a cross-section per unit time. A fluid column of length vΔt and area A has volume AvΔt, so:
- Q
- volume flow rate (m³ s⁻¹)
| Quantity | Expression | SI unit |
|---|---|---|
| Volume flow rate | Q = Av | m³ s⁻¹ |
| Mass flow rate | ρAv | kg s⁻¹ |
| Steady incompressible condition | A₁v₁ = A₂v₂ | same Q at both sections |
Area-Speed Relation
When Q is constant, speed varies inversely with cross-sectional area. A narrow section has greater speed; a wide section has smaller speed.
Applications
- A freely falling water stream accelerates, so its cross-sectional area decreases.
- Squeezing a rubber hose reduces its opening and increases water speed.
- For the same river discharge, a deep or wide region has larger area and slower average flow.
- Blood from the aorta divides among many arteries; their combined area controls the new speed.
- Pipe and duct systems use continuity at changing cross-sections.
Solved Examples
Example 1: Narrow Pipe
Water flows at 2.0 m s⁻¹ through area 6.0 cm². Find its speed where area becomes 3.0 cm².
- A₁ = 6.0 cm²
- v₁ = 2.0 m s⁻¹
- A₂ = 3.0 cm²
A₁v₁ = A₂v₂
v₂ = A₁v₁/A₂
v₂ = 6.0 × 2.03.0
Final answer: v₂ = 4.0 m s⁻¹
Example 2: Volume Flow Rate
A pipe of radius 2.0 cm carries water at 1.5 m s⁻¹. Calculate Q.
- r = 2.0 × 10⁻² m
- v = 1.5 m s⁻¹
A = πr² = π(2.0 × 10⁻²)²
A = 1.26 × 10⁻³ m²
Q = Av
Q = (1.26 × 10⁻³)(1.5)
Final answer: Q = 1.88 × 10⁻³ m³ s⁻¹
Example 3: Textbook Blood-Flow Example
Blood moves through an aorta of radius 0.8 cm at 0.33 m s⁻¹ and divides equally into 30 arteries of radius 0.4 cm. Find the speed in each artery.
- r₁ = 0.8 cm
- v₁ = 0.33 m s⁻¹
- N = 30
- r₂ = 0.4 cm
A₁v₁ = 30A₂v₂
Use A = πr² and cancel π.
v₂ = (130)(r₁r₂)²v₁
v₂ = (130)(0.80.4)²(0.33)
Final answer: v₂ = 0.044 m s⁻¹
Example 4: Deep and Shallow River
Explanation: The comparison assumes the same volume flow rate.
Branched Flow
At a junction, total inflow equals total outflow. If one inlet divides into N identical outlets:
- N
- number of identical outlets (none)
Common Mistakes
- Using A₁v₁ = A₂v₂ when density changes significantly.
- Forgetting to include every outlet branch.
- Using radius directly instead of A = πr².
- Mixing cm² with m² when calculating Q.
- Saying speed is inversely proportional to radius instead of area.
- Assuming continuity alone determines pressure.
Short-Question Preparation
Q. What principle gives continuity?
A. Conservation of mass.
Q. State the general equation.
A. ρ₁A₁v₁ = ρ₂A₂v₂.
Q. State it for an incompressible fluid.
A. A₁v₁ = A₂v₂, or Av = constant.
Q. Define volume flow rate.
A. Q = ΔVΔt = Av.
Q. Why does water speed up at a squeezed hose end?
A. Area decreases, so speed increases to keep Av constant.
Long-Question Preparation
Q. Derive the equation of continuity.
A. 1. Take two sections during the same Δt. 2. Write Δx₁ = v₁Δt and Δx₂ = v₂Δt. 3. Volumes are A₁v₁Δt and A₂v₂Δt. 4. Masses are ρ₁A₁v₁Δt and ρ₂A₂v₂Δt. 5. Conserve mass and cancel Δt. 6. Obtain ρ₁A₁v₁ = ρ₂A₂v₂. 7. For constant density, obtain A₁v₁ = A₂v₂ = constant. 8. Identify Av as Q and explain v ∝ 1A.
Sticky Notes
- Continuity = conservation of mass.
- General: ρ₁A₁v₁ = ρ₂A₂v₂.
- Incompressible: A₁v₁ = A₂v₂.
- Q = Av.
- Mass flow rate = ρAv.
- Circular area = πr².
- Smaller area → greater speed.
60-Second Revision
| Area change | Speed change |
|---|---|
| decreases | increases |
| increases | decreases |
| halves | doubles |
| becomes one-fourth | becomes four times |
Summary
Continuity expresses conservation of mass. The mass flow rate ρAv remains constant during steady flow. If density is constant, Av and Q remain constant, producing the inverse relation between area and speed.
Ask-the-Tutor Modes
- Explain continuity simply.
- Show the full derivation.
- Help me choose the correct form.
- Solve an area-speed numerical.
- Solve a branched-flow problem.
- Explain an application.
- Test me with an MCQ.
Exam Focus
Exam Focus
Important points
- Mass-conservation derivation
- General density form
- Incompressible form
- Q = Av
- Area-speed relation
- Branched flow
Important formulas
- ρ₁A₁v₁ = ρ₂A₂v₂
- A₁v₁ = A₂v₂
- Q = ΔVΔt = Av
- A = πr²
- A₁v₁ = NA₂v₂
Common exam traps
- Not squaring radius
- Omitting branches
- Ignoring density change
- Mixing area units
Short question tips
- State assumptions with the reduced form.
Long question structure
Setup → distance → volume → mass → conservation → general form → incompressible form → applications.
Common Mistakes
Common Mistakes
- Mistake
Use the density form for compressible flow.
- Mistake
Use cross-sectional area, not radius.
- Mistake
Count every outlet branch.
- Mistake
Continuity does not directly calculate pressure.
Revision Zone
60-Second Revision
Quick cues from this topic — use them for last-minute revision.
ρAv is constant.
For incompressible flow, Av is constant.
Q = Av.
v ∝ 1A.
Continuity expresses conservation of mass in steady fluid flow.
ρ₁A₁v₁ = ρ₂A₂v₂; A₁v₁ = A₂v₂
- Definition
- Continuity expresses conservation of mass in steady fluid flow.
- Formula
- ρ₁A₁v₁ = ρ₂A₂v₂; A₁v₁ = A₂v₂
- Example
- A hose jet speeds up when its opening is narrowed.
- Critical warning
- For a circular pipe, use A = πr².
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Exam Practice
Important Short Question
Q1. State continuity for an incompressible fluid.
Important Short Question
Q2. Define volume flow rate and give its SI unit.
Conceptual Question
Q3. Why does a falling water stream become narrower?
Long Question Preparation
Q4. Derive continuity and discuss applications.