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Series
Series calculations use Rₜ = R₁ + R₂ + ..., equal current through all components, and voltage drops that sum to the supply voltage.
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Series
For series calculations:
Step 1: Add resistances.
Step 2: Find current.
Step 3: Find each voltage drop.
Recommended for Class 10
Series
This topic applies the rules of series connections to circuit calculations.
For resistors in series:
Rₜ = R₁ + R₂ + ...
Current:
I = I₁ = I₂ = ...
Potential difference:
Vₜ = V₁ + V₂ + ...
Example
A 4 Ω and 8 Ω resistor are connected in series to 24 V.
Total resistance:
**Rₜ = 4 + 8 = 12 Ω**
Current:
**I = VR**
**I = 2412 = 2 A**
Voltage across 4 Ω:
**V₁ = IR₁ = 2 × 4 = 8 V**
Voltage across 8 Ω:
**V₂ = IR₂ = 2 × 8 = 16 V**
Check:
**8 + 16 = 24 V**
Voltage Division
Because the same current passes through both resistors:
**V₁V₂ = R₁R₂**
A larger resistance therefore has a larger voltage drop.
Series — Advanced
Series circuits form a voltage divider because identical current through unequal resistances produces voltage drops proportional to their resistances.
Common Mistakes
Common Mistakes
- Mistake
Mistake: Finding current before total resistance. Correction: Always calculate total resistance before finding total current.
- Mistake
Mistake: Splitting current in a series circuit. Correction: Do not split current in a series circuit.
Revision Zone
60-Second Revision
Quick cues from this topic — use them for last-minute revision.
R adds.
I same.
V divides.
- Definition
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Practice
PQ
Q1. Calculate total series resistance.
PQ
Q2. Calculate circuit current.
PQ
Q3. Calculate voltage drop across first resistor.
PQ
Q4. Calculate voltage drop across second resistor.
PQ
Q5. Verify voltage drops sum to supply voltage.
Exam Practice
EQ
Q1. Derive/use series rules.
EQ
Q2. Solve two-resistor circuit.
EQ
Q3. Explain voltage division.
EQ
Q4. Verify voltage sum.
EQ
Q5. Explain current equality.
School-standard facts for Matric and Intermediate. Original explanations — not copied from textbooks.