Topic 11.174 min read
Potentiometer and Null Measurement
A potentiometer measures or compares emf by balancing it against the potential drop along a uniform wire. At balance, the test cell supplies no current, so loading error is avoided.
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A potentiometer uses a long, uniform resistance wire as a voltage scale. A steady driver current makes equal wire lengths have equal potential drops.
Move the jockey until the galvanometer shows zero. At this balance or null point, the test cell sends no current through the galvanometer branch.
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For potential difference V across uniform wire length L, potential gradient is the potential drop per unit length.
At balance, V_l equals test emf ε. If two cells are balanced without changing driver current, k stays constant.
- Use a uniform wire and steady driver current.
- Connect correct polarity so the test emf opposes the wire drop.
- Maximum wire drop must be at least the test emf.
- Smaller k gives a longer balance length and greater sensitivity.
To find internal resistance, first measure open-circuit balance length l₁. Connect known resistance R across the cell and measure terminal-voltage balance length l₂.
The null method avoids loading error because the test cell supplies no current at balance.
Exam Focus
Exam Focus
Important points
- Potential gradient
- Null condition
- Emf comparison
- Accuracy
- Sensitivity
Important formulas
- k=VL
- ε=kl
- ε1ε2=l1l2
- r=R(l1l2-1)
Common exam traps
- Null does not mean zero emf.
- Ratio requires unchanged k.
Short question tips
- State formula conditions.
Long question structure
Circuit → gradient → null → derivation → conditions
Common Mistakes
Common Mistakes
- Mistake
Treating null as zero emf.
- Mistake
Changing driver current between readings.
- Mistake
Reversing l₁ and l₂.
- Mistake
Writing k=L/V.
- Mistake
Ignoring polarity or range.
Revision Zone
60-Second Revision
Quick cues from this topic — use them for last-minute revision.
Constant gradient
Zero test-branch current at balance
No loading error
Emf proportional to balance length
A potentiometer balances an unknown emf against the potential drop along a uniform wire.
k=VL, ε=kl, ε1ε2=l1l2
- Definition
- A potentiometer balances an unknown emf against the potential drop along a uniform wire.
- Formula
- k=VL, \quad \varepsilon=kl, \quad ε1ε2=l1l2
- Example
- For 60 cm and 40 cm, ε₁ε₂=32.
- Critical warning
- Driver current still flows at null.
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Exam Practice
Define
Q1. Define potential gradient.
Explain
Q2. Why is this a null method?
Derive
Q3. Compare two emfs.
Calculate
Q4. If l₁=75 cm, l₂=50 cm and ε₂=1.2 V, find ε₁.
Reason
Q5. Why does smaller k improve sensitivity?